Rule

Take the dimensions, in inches and decimal parts of an inch. Square the diameter, multiply it by the length in inches, and then multiply the product by .0034 for Wine Gallons, or by •002785 for Ale Gallons.

Example

How many U. S. Gallons will a Cylindrical Vessel contain, whose diameter is 9 inches, and length 9½ inches?

Diameter,

9

Brought up

769.6

9

•0034

Square Diam

. 81

30780

Length,

9.6

23086

406

2.61680

729

or 2 gallons and 6 pints.

Carried up, 769.5

To Ascertain the Weights of Pipes of various Metals, and any Diameter required.

Thickness in parts of an inch.

Wrought iron.

Copper.

Lead.

1/32

•326

11½ lbs. plate .38

2 lbs. lead .488

1/16

.653

23½ " .76

4 " .967

3/32

.976

35 " 114

5½ " 1.45

1/8

1.3

46½ •• 1.52

8 " 1.933

5/32

1.627

58 " 1.9

9½ " 2.417

3/16

1.95

70 " 2.28

11 " 2.9

7/32

2.277

80½ " 2.66

13 " 8.383

1/4

2.6

93 •« 804

15 " 8.867

RulE - the interior diameter of the pipe, in inches, add the thickness of the metal; multiply the sum by the decimal numbers opposite the required thickness and under the metal's name; also by the length of the pipe in feet, and the product is the weight of the pipe in lbs.

1. Required the weight of a copper pipe whose interior diameter is 7½ inches, its length 6¼ feet, and the metal \ of an inch in thickness.

7.5 X .125 = 7.625 X 1.52 X 6.25 = 72.4 lbs.

2. What is the weight of a leaden pipe 18½ feet in length, 3 inches interior diameter, and the metal ¼ of an inch in thickness?

3 + .25 = 3.25 X 3.867 X 18.5 = 232.5 lbs.