Let a b c be the angle which the pediment makes with the cornice, and let the form and size of the moulding be as in the last problem, and as shown at d a b H. From D drop a perpendicular on c b, and draw D E perpendicular to d c, or parallel to C b ; and let d e be equal to E I (Fig. 40). Then from E draw E F parallel to d a, and divide e f into the same number of parts as I K (Fig. 40), at 1 a, 2 b, 8 c, and transfer the distances 1 a. 2 b, 3 c, as in Fig. 40. Then a curve line drawn through the points a, b, c, will be the form of the return for the moulding of the open pediment. The mitre for the return is cut in the usual manner, but that of the pediment is cut to the proper angle of its inclination, as in the last problem. In fixing the mitre, the portion R D G of the return must be cut away to make it come flush with the top of the pediment moulding.

Fig. 40.

Fig. 41.