To Find The Contents In V. S. Standard Gallons Of The Frustrum Of A Cone

Rule. - To the product of the diameters in inches, and decimal parts of an inch of the ends, add 1/3 the square of the difference of the diameters Multiply the sum by the perpendicular height in inches and decimal parts of an inch, and multiply that product by .0034 for Wine gallons, and by .002785 for Beer gallons.

Example. - The diameter of the large end of a Frustrum of a Cone, fig. 14, is 8 feet, that of the smaller end is 4 feet, and the perpendicular height 10 feet - what is the Contents in U. S. Standard gallons ?

96 - 48 = 482 = 2304 ÷ 3 - 768; 96 X 48 + 768 = 5376 X 120 X .0034 = 2193.4 gallons.

To Find The Solidity Of The Frustrum Of A Pyramid

Rule. - Add to the areas of the two ends of the Frustrum, the square root of their product, and this sum multiplied by 1/3 of the perpendicular height will give the Solidity.

Example. - What is the Solidity of a hexagonal pyramid, fig. 15, a side of the large end AB, being 12 feet, and one of the smaller ends 6 feet, and the perpendicular height 8 feet ?

874.122 + 93.53 = √ 34991.63 = 590.811 374.122 + 93.53 ÷

1058. .463 X 8 590.811 = ----------------------= 2822.568 Cubic ft. the Solidity.

Fig. 15.

To Find The Solidity Of A Sphere

Rule. - Multiply the Cube of the diameter by .5236 and the product is the Solidity.

Example. - What is the Solidity of a Sphere, fig. 15, the diameter being 20 inches ?

203 = 8000 X .5236 = 4188.8 Cubic inches the Solidity.

Tables Of Weights, &C

Weight of Square Rolled Iron, from 1-4 Inch to 12 Inches, and 1 Foot in Length.

Weight of Flat Boiled Iron from 1- 8 X 1-2 Inch to

1 X 6 Inches.

Weight of Round Rolled Iron from 1-4 Inch to 12 Inches in Diameter, and 1 foot in Length.

Weight of a Square Foot of Wrought Iron, Copper and Lead, from 1-16 to 2 Inches thick.

Weight of Copper Bolts from 1-4 to 4 Inches in Diameter, and 1 foot in Length.