On distillation with dehydrating agents, e.g., sulphuric acid or zinc chloride, primary alcohols have the elements of water removed and yield unsaturated hydrocarbons: -

CH3.CH1 .CH1.OH

-

H1O

=

CH3.CH:CH1.

Propyl alcohol.

Propylene.

On treating the hydrocarbon with concentrated hydriodic acid, the iodine atom attaches itself to the carbon having least hydrogen, forming a secondary iodide: -

CH3.CH:CH1

+

HI

=

CH3.CHI.CH3

Propylene.

Isopropyl iodide.

When the iodide is treated with moist silver oxide, the iodine atom is replaced by a hydroxyl group according to the general method (1), above, thus yielding a secondary alcohol: the resulting product would have been a tertiary alcohol: -

CH3 .CHI.CH3 + AgOH = CH3.CH(OH).CH3 + Agl.

Isopropyl alcohol.

If, instead of starting with propyl alcohol, we had taken isobutyl alcohol, which contains the primary group -CH1.OH united to a secondary radical

Conversion Of Primary Alcohols Into Secondary And  60Conversion Of Primary Alcohols Into Secondary And  61Conversion Of Primary Alcohols Into Secondary And  62