Example 1

Required the quantity of materials for a 12-inch thick basement wall, 6 feet 5 inches high above footing, for a house 25 feet by 40 feet outside dimensions. The footing 1 foot 6 inches wide and 6 inches thick. Concrete proportioned 1 :3 :5.

Wall.

Length of wall 25+25+39+39=128 ft. Height of wall 6 ft. 5 in. = 6 5/12 = 6.417 ft. Area of wall = 128 X 6.417 - 821.4 sq. ft. Thickness of wall = 12 in.

Quantities of materials for wall concrete: Factor for multiplying units in

Take 9.86

Sacks of cement = 14.2 X 9.86 - 140.0 Cu. yd. of sand = 1.58 X 9.86 = 15.6

Cu. yd. of pebbles or crushed stone = 2.64 X 9.86 = 26.0 Footing.-

Length of footing - 25.5 + 25.5 + 37.5 + 37.5 = 126 ft. Width of footing = 1 ft. 6 in. = 1 6/12 = 1.5 ft. Area of footing = 126 X 1.5 = 189 ft. Thickness of footing = 6 in. Quantities of materials for footing:

Factor for multiplying units in the

Sacks of cement = 14.2 X 1.13 - 16.0 Cu. yd. of sand = 1.58 X 1.13 = 1.8 Cu. yd. of pebbles or stone = 2.64 X 1.13 = 3.0 Total quantities of materials:

Sacks of cement - 140 + 16 - 156.0

Cu. yd. of sand = 15.6 + 1.8 = 17.4 or 17.5

Cu. yd. pebbles = 26.0 + 3 = 29.0

Example 2

Required the quantities for a concrete floor for a basement. Interior dimensions of the basement 23 feet by 38 feet. Floor 5 inches thick over all, with 4-inch base of concrete proportioned 1:2 1/2 :5, and 1-inch wearing course composed of cement mortar proportioned 1 :2.

Area of floor = 23 X 38 = 874 sq. ft.

Factor for multiplying quantities in table for

Quantities of materials for base concrete:

Sacks of cement = 15.4 X 3.5 = 54.0

Cu. yd. of sand = 1.43 X 3.5 = 5.0

Cu. yd. of pebbles or stone = 2.86 X 3.5 - 10.0

Factor for multiplying quantities in table for

Quantities of materials for wearing surface mortar: Sacks of cement = 39.4 X .9 = 35.5 Cu. yd. of sand = 2.92 X .9 = 2.6 cu. yd.

Total quantities of materials for floor:

Sacks of cement = 54.0 + 35.4 - 89.5 Cu. yd. of sand = 5.0 + 2.6 - 7.6 or 7.5 Cu. yd. of pebbles or stone = 10.0